2x^2-0,08=0

Solution for 2x^2-0,08=0 equation:

2x^2-0.08=0

a = 2; b = 0; c = -0.08;
Δ = b2-4ac
Δ = 02-4·2·(-0.08)
Δ = 0.64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.64}}{2*2}=\frac{0-\sqrt{0.64}}{4}
=-\frac{\sqrt{}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.64}}{2*2}=\frac{0+\sqrt{0.64}}{4}
=\frac{\sqrt{}}{4}
$